Specific Heat Calculator

Specific Heat Calculator:

Enter the values of heat energy, Q_(J), mass, m_(g) and temperature change, T_(°C) to determine the value of Specific Heat, c_(J/g.°C).

Enter Heat Energy :		J
Enter Mass :		g
Enter Temperature :		°C
Result – Specific Heat :		J/g°C

Specific Heat Formula:

Specific heat is a physical property of a substance that represents the amount of heat energy required to raise the temperature of a unit mass of the substance by one degree Celsius (or Kelvin).

It measures the thermal capacity of a material and is typically expressed in joules per gram per degree Celsius (J/g·°C) or joules per kilogram per Kelvin (J/kg·K). The specific heat of a material depends on its molecular structure and the state of matter (solid, liquid, or gas).

Materials with high specific heat can absorb and store large amounts of heat energy without significant changes in temperature. This property plays a crucial role in processes involving heat transfer, such as heating, cooling, and phase transitions.

Specific heat is essential in fields like thermodynamics, engineering, meteorology, and material science to understand and calculate energy flow. It helps design efficient systems like heaters, insulators, and cooling mechanisms.

The value of specific heat varies among different substances; for example, water has a high specific heat, making it an excellent coolant and temperature stabilizer.

Specific Heat, c_(J/g.°C) in Joules per gram-degree Celsius equals the heat energy, Q_(J) in Joules divided by the product of the mass, m_(g) in grams and the temperature change, T_(°C) in degree Celsius.

Specific Heat, c_(J/g·°C)  = Q_(J) /m_(g) * T_(°C)

c_(J/g.°C)  = specific heat in Joules per gram-degree Celsius, J/g°C.

Q_(J) = heat energy in Joules, J.

m_(g) = mass in grams, g.

T_(°C) = temperature in degree Celsius, °C.

Specific Heat Calculation:

1.A metal block of mass 500 g is heated with 10,000 J of energy, causing its temperature to rise by 40°C. Calculate the specific heat of the metal.

Given:Q_(J) = 10000J, m_(g) = 500g, T_(°C) = 40°C.

Specific Heat, c_(J/g·°C)  = Q_(J) /m_(g) * T_(°C)

c_(J/g·°C)  = 10000 / 500 * 40

c_(J/g·°C)  = 0.5J/g°C.

2.A substance with a mass of 2 kg has a specific heat of 2J/g°C. If its temperature increases by 25°C, calculate the heat energy required.

Given:c_(J/g·°C)  = 2J/g°C, m_(g) = 2000g, T_(°C) = 25°C.

Specific Heat, c_(J/g·°C)  = Q_(J) /m_(g) * T_(°C)

Q_(J) =c_(J/g·°C) *m_(g) * T_(°C)

Q_(J) = 2 * 2000 * 25

Q_(J) = 100000J.