RLC Circuit Frequency Calculator

RLC Circuit Frequency Calculator:

Enter the values of inductance, L(H) and capacitance, C(F) to determine the value of Frequency, f(Hz).

Enter Inductance : H
Enter Capacitance : F
   
Result – Frequency : Hz

RLC Circuit Frequency Formula:

An RLC circuit is an electrical circuit consisting of a resistor (R), inductor (L), and capacitor (C), connected in series or parallel. This circuit is commonly used in signal processing, filtering, and oscillators due to its ability to resonate at a specific frequency. Resonance occurs when the inductive reactance equals the capacitive reactance, and the circuit’s impedance is purely resistive.

The resonance frequency is the frequency at which the circuit naturally oscillates. At this frequency, the energy alternates between the inductor’s magnetic field and the capacitor’s electric field, with minimal energy dissipated as heat in the resistor. The resonance frequency depends on the values of the inductor (L) and capacitor (C) but is independent of the resistance (R).

The formula for the resonance frequency of an RLC circuit is derived based on the natural frequency of oscillation, assuming no damping. It is calculated as the reciprocal of two times pi times the square root of the product of inductance (L) in henries (H) and capacitance (C) in farads (F).

Frequency f(Hz)in Hertz equals one divided by the product of 2 pi, square root of inductance, L(H) in Henries and capacitance, C(F)in Farads.

Frequency, f(Hz) = 1 / (2 * 3.14 * √(L(H) * C(F)))

f(Hz) = frequency in Hertz, Hz.

L(Ω) = inductance in Henries, H.

C(F) = capacitance in Farads, F.

RLC Circuit Frequency Calculation:

1.An RLC circuit has an inductor with 0.2H and a capacitor with 50μF (50×10−6F). Calculate the resonance frequency of the circuit.

Given: L(Ω) = 0.2H, C(F) = 50 * 10−6F.

Frequency, f(Hz) = 1 / (2 * 3.14 * √(L(H) * C(F)))

f(Hz) = 1 / (2 * 3.14 * √(0.2 * 50 * 10−6))

f(Hz) = 1 / (2 * 3.14 * √0.00001)

f(Hz) = 1 / 0.01987

f(Hz) = 50.33Hz.

2.An RLC circuit resonates at 1000Hz with a capacitor of 10μF (10×10−6F). Calculate the inductance of the circuit.

Given: C(F) = 10 * 10−6F, f(Hz) = 1000Hz.

Frequency, f(Hz) = 1 / ((2 * 3.14 * f(Hz))2* C(F))

L(Ω)= 1 / ((2 * 3.14 * 1000)2* 10 * 10−6)

L(Ω)= 1 / (39478417.6 * 10 * 10−6)

L(Ω)= 1 / 394.784

L(Ω)= 0.00253H.

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