Pressure Depth Calculator

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Pressure Depth Calculator:

Enter the values of density, ρ(kg/m3), acceleration due to gravity, g(m/s2) and depth, d(m) to determine the value of Pressure, P(Pa).

Enter Density: kg/m3
Enter Acceleration Due to Gravity: m/s2
Enter Depth: m
   
Result – Pressure: Pa

Pressure Depth Formula:

Pressure depth refers to the pressure exerted on an object or substance due to the weight of the fluid above it. It is a concept used primarily in fluid mechanics, especially in underwater or atmospheric scenarios, where the pressure increases with depth. The deeper an object is submerged in a fluid, the greater the pressure it experiences. This is due to the weight of the fluid column above the object, and the pressure is proportional to the density of the fluid, the depth, and the gravitational acceleration.

In fluids like water, air, or any other liquid, pressure at a certain depth is determined by the weight of the fluid above that point. The pressure increases with depth because the weight of the fluid increases. The pressure at any point in a fluid is isotropic, meaning it acts equally in all directions.

The formula used to calculate pressure at a certain depth in a fluid is based on three factors: the fluid density (ρ), the gravitational acceleration (g), and the depth (d). The equation is essential in various fields, such as diving, engineering, meteorology, and oceanography, as it helps in understanding the behaviour of fluids under pressure.

Pressure, P(Pa) in Pascals equals the density, ρ(kg/m3) in kilogram per cubic metres of the fluid multiplied by the acceleration due to gravity, g(m/s2) in metres per second squared and then multiplied by the depth, d(m) in metres of the fluid.

Pressure, P(Pa) = ρ(kg/m3) * g(m/s2) *  d(m)

P(Pa) = pressure in Pascals, Pa.

ρ(kg/m3) = density in kilogram per cubic metres, kg/m3.

g(m/s2) = acceleration due to gravity in metres per second squared, m/s2.

d(m) = depth in metres, m.

Pressure Depth Calculation:

  1. A diver is 50 meters underwater in the ocean, where the density of seawater is 1025 kg/m3, and the acceleration due to gravity is 9.8 m/s2. Calculate the pressure at that depth.

Given: ρ(kg/m3) = 1025 kg/m3, g(m/s2) = 9.8 m/s2, d(m) = 50m.

Pressure, P(Pa) = ρ(kg/m3) * g(m/s2) *  d(m)

P(Pa) = 1025 * 9.8 * 50

P(Pa) = 502250Pa.

  1. The pressure at a certain depth in the ocean is 600000Pa Pascals, with seawater having a density of 1030 kg/m3 and the gravitational acceleration being 9.81 m/s2. Find the depth.

Given: ρ(kg/m3) = 1030 kg/m3, g(m/s2) = 9.81 m/s2, P(Pa) = 600000Pa.

Pressure, P(Pa) = ρ(kg/m3) * g(m/s2) *  d(m)

d(m) = P(Pa) / ρ(kg/m3) * g(m/s2)

d(m) = 600000 / 1030 * 9.81

d(m) =  59.38m.

 

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