Neutralization Reaction Calculator

Neutralization Reaction Calculator:

Enter the values of weight, W_(g),  volume, V_(L) and normality, N_(eq/L) to determine the value of Equivalent Weight, EW_(g/eq).

Enter Weight:		g
Enter Volume:		L
Enter Normality:		eq/L
Result – Equivalent Weight:		g/eq

Neutralization Reaction Formula:

A neutralization reaction is a chemical process in which an acid and a base react to form salt and water. This reaction occurs when hydrogen ions (H⁺) from the acid combine with hydroxide ions (OH^–) from the base, resulting in the formation of water (H₂O). The salt produced depends on the specific acid and base involved in the reaction.

Neutralization reactions are exothermic, meaning they release heat. The extent of neutralization is determined by the equivalent weight (EW) of the acid or base, which represents the amount of substance required to react with one mole of H⁺ or OH^– ions. The equivalent weight of an acid is calculated by dividing its molar mass by the number of replaceable hydrogen ions, while for bases, it is the molar mass divided by the number of hydroxide ions it can provide.

This calculation is essential in various applications, including titration in analytical chemistry, wastewater treatment, and industrial chemical reactions. Understanding the neutralization process helps in determining the normality (N) of solutions, which is the concentration of equivalent weights per liter of solution.

Equivalent Weight, EW_(g/eq) in grams per equivalent is equal to the weight, W_(g) of the acid or base in grams divided by the product of the volume, V_(L) of the solution in litres and the normality, N_(eq/L) of the solution in equivalents per litre.

Equivalent Weight, EW_(g/eq) = W_(g) / V_(L) * N_(eq/L)

EW_(g/eq) = equivalent weight in grams per equivalent, g/eq.

W_(g) = weight in grams, g.

V_(L) = volume in litres, L.

N_(eq/L) = normality in equivalent per litre, eq/L.

Neutralization Reaction Calculation:

1. A chemist dissolves 10g of hydrochloric acid (HCl) in 2L of solution, and the normality of the solution is 0.5 eq/L. Calculate the equivalent weight of Hcl.

Given: W_(g) = 10g, V_(L) = 2L, N_(eq/L) = 0.5eq/L.

Equivalent Weight, EW_(g/eq) = W_(g) / V_(L) * N_(eq/L)

EW_(g/eq) = 10 / 2 * 0.5

EW_(g/eq) = 10g/eq.

2. A 3L solution has a normality of 0.2 eq/L, and the equivalent weight of sulfuric acid (H₂SO₄) is 49 g/eq. Calculate the weight of sulfuric acid present in the solution.

Given: EW_(g/eq) = 49g/eq, V_(L) = 3L, N_(eq/L) = 0.2eq/L.

Equivalent Weight, EW_(g/eq) = W_(g) / V_(L) * N_(eq/L)

W_(g) = EW_(g/eq) * V_(L) * N_(eq/L)

W_(g) = 49 * 3 * 0.2

W_(g) = 29.4g.