High Pass Filter Calculator

by

High Pass Filter Calculator:

Enter the values of resistance, R(Ω) and capacitance, C(F) to determine the value of Cut-off Frequency, fc(Hz).

Enter Resistance: Ω
Enter Capacitance: F
   
Result – Cut-Off Frequency: Hz

High Pass Filter Formula:

A High Pass Filter (HPF) is an electronic circuit designed to allow signals with frequencies higher than a certain cut-off frequency (fc) to pass through while attenuating signals with frequencies lower than the cut-off. It is commonly used in audio processing, telecommunications, and signal conditioning applications.

The HPF typically consists of a resistor (R) and a capacitor (C) connected in series or parallel. The cut-off frequency is determined by the values of the resistor and capacitor in the circuit.

At frequencies above the cut-off, the impedance of the capacitor becomes lower, allowing the signal to pass through. At frequencies below the cut-off, the capacitor blocks low-frequency signals by creating a high impedance path.

The cut-off frequency is the point at which the signal’s power drops to half of its maximum value. Below this frequency, the filter begins to attenuate the signal, and above it, the signal is allowed to pass with little or no attenuation.

Cut-off Frequency, fc(Hz) in Hertz is equal to one divided by the product of 2 times pi, the resistance, R(Ω) in Ohms and the capacitance, C(F) in Farad.

Cut-off Frequency, fc(Hz) = 1 / 2 * 3.14 * R(Ω) * C(F)

fc(Hz) = cut-off frequency in Hertz, Hz.

R(Ω) = resistance in Ohms, Ω.

C(F) = Capacitance in Farads, F.

High Pass Filter Calculation:

  1. Given: R(Ω) = 1000Ω, C(F) = 1 * 10-6F.

Cut-off Frequency, fc(Hz) = 1 / 2 * 3.14 * R(Ω) * C(F)

fc(Hz) = 1 / 2 * 3.14 * 1000 * 1 * 10-6

fc(Hz) = 159.15Hz.

  1. Given: fc(Hz) = 500Hz, C(F) = 0.5 * 10-6F.

Cut-off Frequency, fc(Hz) = 1 / 2 * 3.14 * R(Ω) * C(F)

R(Ω) = 1 / 2 * 3.14 * fc(Hz) * C(F)

R(Ω) = 1 / 2 * 3.14 * 500 * 0.5 * 10-6

R(Ω) = 1 / 1.570795 * 10-3

R(Ω) = 636.62Ω.

Leave a Comment