Resistor Heat Calculator

Resistor Heat Calculator:

Enter the values of current, I(A), resistance, R(Ω) and time, t(s) to determine the value of Resistor Heat, RH(J).

Enter Current : I
Enter Resistance : Ω
Enter Time : s
   
Result – Resistor Heat : J

Resistor Heat Formula:

A resistor generates heat when electrical current flows through it due to its resistance to the flow of electrons. This heat, known as resistor heat (RH), is a result of the energy conversion from electrical energy into thermal energy. The heat generated depends on the current passing through the resistor, the resistance of the material, and the duration of current flow.

This phenomenon is governed by Joule’s Law, which states that the heat energy produced in a conductor is directly proportional to the square of the current (I), the resistance (R), and the time (t) during which the current flows. This relationship makes resistors essential for managing energy dissipation in circuits, preventing overheating or damage to sensitive components.

The resistor’s heat generation is influenced by material type, size, and construction, as these factors determine the resistor’s ability to withstand and dissipate heat. Engineers must account for this heat in circuit designs to ensure safety and efficiency.

Resistor Heat, RH(J) in Joules equals the square of the current, I(A) in amperes, multiplied by resistance, R(Ω) in ohms and the time, t(s) in seconds.

Resistor Heat, RH(J) = I(A)2 * R(Ω) * t(s)

RH(J) = resistor heat in Joules, J.

I(A) = current in amperes, I.

R(Ω) = resistance in ohms, Ω.

t(s) = time in seconds, s.

Resistor Heat Calculation:

1.A resistor with a resistance of 10Ω carries a current of 2A for 60s. Find the heat generated.

Given: I(A) = 2A, R(Ω) = 10 Ω,t(s) = 60s.

Resistor Heat, RH(J) = I(A)2 * R(Ω) * t(s)

RH(J) = 22 * 10 * 60

RH(J) = 2400J.

2.A resistor generates 3600J of heat when a current of 3A flows through it for 40s. Calculate the resistance.

Given: I(A) = 3A, RH(J) = 3600J,t(s) = 40s.

Resistor Heat, RH(J) = I(A)2 * R(Ω) * t(s)

R(Ω) = RH(J) / I(A)2 * t(s)

R(Ω) = 3600 / 32 * 40

R(Ω) = 10Ω.

 

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