Applied Force Calculator

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Applied Force Calculator:

Enter the values of  mass, m(kg), acceleration, a(m/s2) and  frictional force, FF(N) to determine the value of Applied Force, AF(N).

Enter Mass: kg
Enter Acceleration: m/s2
Enter Frictional Force: N
   
Result – Applied Force: N

Applied Force Formula:

The applied force (AF) is the force exerted on an object due to an external action or interaction. It is a vector quantity, meaning it has both magnitude and direction. Applied forces can cause an object to move, accelerate, or change its state of motion.

This force is responsible for initiating or altering the motion of an object in accordance with Newton’s second law of motion. It can appear in various forms, including push, pull, and frictional forces. The applied force may oppose other forces acting on the object, such as gravitational or frictional forces.

The total effect of an applied force depends on factors such as the magnitude, direction, and point of application. It plays a significant role in understanding how objects behave under different conditions, from simple mechanical systems to complex structures.

Applied Force, AF(N) in Newtons is calculated as the product of mass, m(kg) in kilograms and acceleration, a(m/s2) in metres per second squared from which the frictional force, FF(N) in Newtons is subtracted.

Applied Force, AF(N) = m(kg) * a(m/s2) – FF(N)

AF(N) = applied force in Newtons, N.

m(kg) = mass in kilograms, kg.

a(m/s2) = acceleration in metres per second squared, m/s2.

FF(N) = frictional force in Newtons, N.

Applied Force Calculation:

  1. A 5 kg object is accelerating at a rate of 2 m/s2, and the frictional force acting on it is 3 N. Calculate the applied force on the object.

Given: m(kg) = 5kg, a(m/s2) = 2m/s2, FF(N) = 3N.

Applied Force, AF(N) = m(kg) * a(m/s2) – FF(N)

AF(N) = 5 * 2 – 3

AF(N) = 10 – 3

AF(N) = 7N.

  1. An object experiences an applied force of 20 N, and the frictional force acting on it is 4 N. The object has a mass of 6 kg. Calculate the acceleration of the object.

Given: m(kg) = 6kg, AF(N) = 20N, FF(N) = 4N.

Applied Force, AF(N) = m(kg) * a(m/s2) – FF(N)

a(m/s2) = AF(N) + FF(N) / m(kg)

a(m/s2) = 20 + 4 / 6

a(m/s2) = 4m/s2.

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